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Elementary linear algebra larson pdf

elementary linear algebra larson pdf

Introduction to elementary linear algebra larson pdf:

Linear algebra is one of the subtopics in algebra. Algebra is classified into many subtopics like linear, non linear, quadratic, inequalities, system of equations. Linear algebra is one of the important topics in algebra. Linear algebra deals with variables and numbers. Simple linear equation consists of one variables and a constant. In elementary level, simple linear algebra is followed. Linear equation means, the x axis varies linearly with respect to the y – axis.

Elementary linear algebra Larson PDF:

Ron Larson, mathematician in the Penn State Erie, The Behrend College, Pennsylvania. He wrote lot of books in math for intermediate level and also for the college level. He is well known for his article publishing and text books. His books mainly deal with algebra and pre algebra. Larson pdf in elementary linear algebra is an excellent pdf for intermediate students. This elementary linear algebra pdf file provides many simple problems and answers in linear algebra. Larson pdf for elementary linear algebra is useful for learning basic linear algebra problems.

elementary linear algebra larson pdf- problems:

Example 1:

Solve the linear equation

x + 10 = 25

Solution:

x + 10 = 25

Subtract 10 on both sides,

X + 10 – 10 = 25 – 10

X = 15

The answer is 15.

Example 2:

Solve the linear equation

2y + 20 = 40

Solution:

2y + 20 = 40

Subtract 20 on both sides,

2y + 20 – 20 = 40 – 20

2y = 20

Divide 2 on both sides,

2y/2 = 20/2

Y = 10

The answer is 10.

Example 3:

Solve the linear equation,

5x + 10 = 2x - 5

Solution:

5x + 10 = 2x – 5

Subtract 10 on both sides,

5x + 10 – 10 = 2x – 5 – 10

5x = 2x – 15

Subtract 3x on both sides,

5x – 2x = -15

3x = -15

Divide 3 on both sides,

3x/3 = -15/3

X = -5

The answer is -5.

Example 4:

Verify x = - 4 is a solution for 3x – 18 = -x – 34

Solution:

3x – 18 = -x – 34

Plug in x = -4 in the given equation,

3(-4) – 18 = - (-4) – 34

-12 – 18 = 4 – 34

-30 = -30

Hence x = -4 is the answer for the given expression.

Example 5:

Solve the linear equation

x + 10 = 25

Solution:

x + 10 = 25

Subtract 10 on both sides,

X + 10 – 10 = 25 – 10

X = 15

The answer is 15.

Example 6:

Solve the linear equation

2y + 20 = 40

Solution:

2y + 20 = 40

Subtract 20 on both sides,

2y + 20 – 20 = 40 – 20

2y = 20

Divide 2 on both sides,

2y/2 = 20/2

Y = 10

The answer is 10.

Example 7:

Solve the linear equation,

5x + 10 = 2x - 5

Solution:

5x + 10 = 2x – 5

Subtract 10 on both sides,

5x + 10 – 10 = 2x – 5 – 10

5x = 2x – 15

Subtract 3x on both sides,

5x – 2x = -15

3x = -15

Divide 3 on both sides,

3x/3 = -15/3

X = -5

The answer is -5.

Example 8:

Verify x = - 4 is a solution for 3x – 18 = -x – 34

Solution:

3x – 18 = -x – 34

Plug in x = -4 in the given equation,

3(-4) – 18 = - (-4) – 34

-12 – 18 = 4 – 34

-30 = -30

Hence x = -4 is the answer for the given expression.

Linear algebra deals with variables and numbers. Simple linear equation consists of one variables and a constant. In elementary level, simple linear algebra is followed. Linear equation means, the x axis varies linearly with respect to the y – axis.


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